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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2015

  • question_answer
    The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is

    A) \[N{{H}_{3}},S{{O}_{2}},{{H}_{2}}O\]                                      

    B) \[\text{KMn}{{O}_{\text{4}}}\]

    C) \[{{C}_{2}}O_{4}^{2-}\]        

    D) \[C{{O}_{2}}\]

    Correct Answer: C

    Solution :

    Number to electrons \[=\frac{56\times 100}{170}\] \[=\text{32}.\text{9mgFe}\]                                


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