A) 250J
B) \[\text{25}.0\text{ at}{{\text{m}}^{\text{3}}}\]
C) 500J
D) \[\text{1}.\text{33 at}{{\text{m}}^{\text{3}}}\]
Correct Answer: D
Solution :
Heat produced = Energy stored in capacitor \[{{I}_{AD}}={{I}_{EF}}+\frac{m{{d}^{2}}}{4}\] \[=\frac{m{{d}^{2}}}{12}+\frac{m{{d}^{2}}}{4}\left[ as\,{{I}_{EF}}=\frac{m{{d}^{2}}}{12} \right]\]You need to login to perform this action.
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