A) \[[{{M}^{o}}LT]\]
B) \[[{{M}^{o}}{{L}^{-1}}{{T}^{o}}]\]
C) \[[{{M}^{o}}{{L}^{-1}}{{T}^{-1}}]\]
D) \[[{{M}^{o}}L{{T}^{-1}}]\]
Correct Answer: C
Solution :
We have \[\frac{m{{v}^{2}}}{2}=\frac{9}{4}\] \[v=\frac{3}{\sqrt{2}}m{{s}^{-1}}\] \[=\frac{d}{v}=\frac{2.5}{5}=\frac{1}{2}h\] \[\text{Distance}=\text{7}.\text{5}\times \frac{10}{60}=\text{1}.\text{25 km}\] \[\text{Average speed }=\frac{\text{Total distance}}{\text{Total time}}\] \[=\frac{(2.5+1.25)km}{\left( \frac{40}{60} \right)h}=\frac{45}{8}km/h\]You need to login to perform this action.
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