A) \[4d\]
B) \[4f\]
C) \[\text{CsCl}\]
D) \[{{N}_{2}}{{O}_{4}}\]
Correct Answer: D
Solution :
Let each side of square lamina is d. \[=\frac{1}{2}(10-5)=2.5\] \[(\overset{*}{\mathop{\pi }}\,2P{{x}^{1}})\] According to theorem of perpendicular axis, \[{{O}_{2}}\] \[\because \] ...(i) \[2KMn{{O}_{4}}+5{{H}_{2}}{{C}_{2}}{{O}_{4}}\to 10C{{O}_{2}}+2M{{n}^{2+}}\] \[\therefore \] ...(ii) From Eqs. (i) and (ii), we get \[KMn{{O}_{4}}\] \[=\frac{2\times 126}{5\times 126}\] \[KMn{{O}_{4}}\] \[{{C}_{6}}{{H}_{6}}(I)+\frac{15}{2}{{O}_{2}}(g)\to 6C{{O}_{2}}(g)+3{{H}_{2}}O(I)\]
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