A) NOR gate with output \[{{N}_{2}}{{O}_{4}}\]
B) NAND gate with output \[N{{O}_{2}}\]
C) NAND gate with output \[\text{IUPAC}\]
D) NAND gate with output \[C{{H}_{3}}-C\equiv CH\xrightarrow[1%HgS{{O}_{4}}]{40%{{H}_{2}}S{{O}_{4}}}A\xrightarrow{Isomerisation}\]
Correct Answer: A
Solution :
\[O=\overline{X+Y}\] The logic symbol of NOR gate as shown in the figure Hence the given logic represents NOR gate with output \[\frac{1}{2}{{H}_{2}}(g)+\frac{1}{2}C{{l}_{2}}(g)\to HCl(g);{{\Delta }_{r}}{{H}^{o}};=?\] \[\because \] \[{{\Delta }_{r}}{{H}^{0}}=BE(HCl)-\left\{ \frac{1}{2}BE({{H}_{2}})+\frac{1}{2}BE(C{{l}_{2}}) \right\}\]
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