A) \[{{m}_{3}}\]
B) \[N-{{m}_{3}}\,\,g\sin \theta ={{m}_{3}}a\]
C) Both (a) and (b)
D) None of these
Correct Answer: D
Solution :
Since, A is invertible matrix. \[\therefore \] \[|A|\ne 0\] \[\Rightarrow \] \[\left| \begin{matrix} 1 & 0 & -k \\ 2 & 1 & 3 \\ k & 0 & 1 \\ \end{matrix} \right|\ne 0\] \[\Rightarrow \] \[1(1-0)+k(0-k)\ne 0\] \[\Rightarrow \] \[1-{{k}^{2}}\ne 0\] \[\Rightarrow \] \[k\ne \pm 1\]You need to login to perform this action.
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