A) \[-2\]
B) 2
C) \[=\text{36}0\text{ Hz}\]
D) \[\tau =r\times F\]
Correct Answer: B
Solution :
We have, \[\underset{x\to 1}{\mathop{\lim }}\,\frac{\tan ({{x}^{2}}-1)}{x-1}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{{{\sec }^{2}}({{x}^{2}}-1).2x}{1}\] [Using L? Hospital?s rule] \[=2{{\sec }^{2}}(0)=2\]You need to login to perform this action.
You will be redirected in
3 sec