A) \[HI\] is an exothermic compound
B) \[HI\]is very stable at room temperature
C) \[HI\]is relatively less stable than \[{{H}_{2}}\]and \[{{I}_{2}}\]
D) \[HI\] is resonance stabilized
Correct Answer: C
Solution :
The reaction is endothermic. Calculated value of \[BeC{{l}_{2}}\] is + 22.391 kJ. Thus, HI is relatively less stable than \[\text{BeO}+\text{2HCl}\xrightarrow{{}}\text{ BeC}{{\text{l}}_{\text{2}}}+{{\text{H}}_{\text{2}}}\text{O}\]and \[\text{BeC}{{\text{l}}_{\text{2}}}+\text{ }{{\text{H}}_{\text{2}}}\text{O}\xrightarrow{{}}\text{Be}{{\left( \text{OH} \right)}_{\text{2}}}+\text{HC1}\uparrow \]. \[\text{3}{}^\circ >\text{2}{}^\circ >\text{1}{}^\circ >\overset{+}{\mathop{\text{C}{{\text{H}}_{\text{3}}}}}\,\] \[\text{s}{{\text{p}}^{\text{2}}}\] \[\left( \text{N}{{\text{H}}_{\text{2}}}\text{C}{{\text{H}}_{\text{2}}}\text{COOH} \right)\] or \[\text{alanine }\left( \text{C}{{\text{H}}_{\text{3}}}\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{\text{CH}}}\,\text{COOH} \right)\text{ and}\]
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