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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2015

  • question_answer
    The frequency of the radiation emitted when the electron falls from \[\text{LiCl}>\text{KCl}>\text{NaCl}\]to \[{{C}_{2}}{{H}_{5}}OH\]in a hydrogen atom will be (Given ionization energy of \[C{{H}_{3}}OH\]and\[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{COOH}\]

    A) \[{{\left( \text{C}{{\text{H}}_{\text{3}}} \right)}_{\text{2}}}\text{CHOH}\]          

    B) \[\int_{1}^{4}{{{\log }_{e}}[x]dx}\]

    C) \[\text{lo}{{\text{g}}_{\text{e}}}\text{6}\]                         

    D) \[\text{lo}{{\text{g}}_{\text{e}}}3\]

    Correct Answer: C

    Solution :

    \[\text{phenyl alanine }\left( {{\text{C}}_{6}}{{\text{H}}_{5}}C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  N{{H}_{2}} \end{smallmatrix}}{\mathop{\text{CH}}}\,\text{COOH} \right)\text{ }\] \[{{R}_{2}}Si{{(OH)}_{2}}\]                 Thus,     \[R-N{{H}_{2}}+{{H}_{2}}OR\overset{\oplus }{\mathop{N}}\,{{H}_{3}}+O{{H}^{-}}\]                 \[k=\frac{[R-\overset{\oplus }{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[RN{{H}_{2}}][{{H}_{2}}O]}\]                                           \[k[{{H}_{2}}O]=\frac{[R-\overset{\oplus }{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[R-N{{H}_{2}}]}\]                                 \[{{k}_{b}}=\frac{[R-\overset{+}{\mathop{N}}\,{{H}_{3}}][O{{H}^{-}}]}{[R-N{{H}_{2}}]}\]                                 \[p{{k}_{b}}=-\log {{k}_{b}}\]


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