A) 4, 4
B) 2, 8
C) 1, 8
D) 4, 8
Correct Answer: C
Solution :
\[\therefore \]crystallises with cubic unit cell, with \[\text{CaC}{{\text{l}}_{\text{2}}}\] ions forming the lattice points and \[\therefore \]ion occupying the cubic voids at the body centre. Thus, the unit cell consist of \[\text{CaC}{{\text{l}}_{\text{2}}}=0.0\text{1}\times \text{111}=\text{1}.\text{11 g}\]. \[\text{CaC}{{\text{l}}_{\text{2}}}=\text{111}\] ion and 1 \[\therefore \] ion, which is equivalent to the formula unit \[\text{NaCl}=\text{4}.\text{44}-\text{1}.\text{11}=\text{3}.\text{33}\]. The coordination number of each ion is 8.
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