A) \[c=\frac{2\sqrt{3}+1}{\sqrt{3}}\]
B) \[\text{a}=\text{11},\text{b}=\text{6}\]
C) \[a=-11,b\ne 6\]
D) \[a=11,b\in R\]
Correct Answer: C
Solution :
\[\frac{{{m}_{3}}F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]\[F-{{({{m}_{1}}+{{m}_{2}})}_{g}}\] \[\frac{({{m}_{1}}+{{m}_{2}}+{{m}_{3}})F}{{{m}_{3}}}\] \[1k\Omega \]
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