question_answer

A particular compound of vanadium shows a magnetic moment of 3.86 BM. The oxidation state of vanadium in the compound is \[\text{\hat{i}+\hat{j}}\]

A)  + 3                                        

B) 0

C)  +2                                         

D)  +4

Correct Answer: C

Solution :

Electronic configuration (Z = 23) of vanadium is\[\frac{x}{L}Mg\]. Magnetic moment of vanadium 3.86 BM. Therefore, if has 3 unpaired electrons, in the compound, indicating that  electrons are removed. As such, the oxidation state of vanadium in + 2.