A) 90%
B) 99%
C) 99.9%
D) 100%
Correct Answer: A
Solution :
Observed molecular weight \[h(1-2{{e}^{2}})\] \[A\times B=B\times A\]van?t Hoff factor, \[\frac{\pi }{2}\] and degree of association \[\frac{\pi }{3}\] thus % degree of association \[\frac{\pi }{4}\]You need to login to perform this action.
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