question_answer

A mixture of \[\frac{\pi }{2}\]and \[\frac{\pi }{3}\]of mass 4.44 g is treated with \[\frac{\pi }{4}\] solution to precipitate all \[\frac{\pi }{6}\] ions to \[\frac{{{x}^{2}}}{144}+\frac{{{y}^{2}}}{169}=1\]. It is heated strongly to get 0.56 g of \[\frac{{{x}^{2}}}{169}+\frac{{{y}^{2}}}{144}=1\]. The per cent of \[\frac{{{x}^{2}}}{12}+\frac{{{y}^{2}}}{13}=1\] in mixture (atomic mass Of\[Ca=40\])is

A) 75%                       

B) 30.6%    

C) 25%                       

D) 69.4%