JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    If the vectors \[3\widehat{\mathbf{i}}+\lambda \widehat{\mathbf{j}}+\widehat{\mathbf{k}}\] and \[2\widehat{\mathbf{i}}-\widehat{\mathbf{j}}+8\widehat{\mathbf{k}}\] are perpendicular, then value of \[\lambda \] is:

    A) \[-14\]                                 

    B) \[7\]

    C) \[14\]                                   

    D)  \[1/7\]

    Correct Answer: C

    Solution :

    Key Idea: If \[\overset{\to }{\mathop{\mathbf{a}}}\,\] and \[\overset{\to }{\mathop{\mathbf{b}}}\,\] are two perpendicular vectors, then\[a-b=0\]. Let\[\overset{\to }{\mathop{\mathbf{a}}}\,=3\widehat{\mathbf{i}}+\lambda \widehat{\mathbf{j}}+\widehat{\mathbf{k}}\] and \[\overset{\to }{\mathop{\mathbf{b}}}\,=2\widehat{\mathbf{i}}-\widehat{\mathbf{j}}+8\widehat{\mathbf{k}}\]. Since, they are perpendicular. \[\Rightarrow \]               \[\overset{\to }{\mathop{\mathbf{a}}}\,\cdot \overset{\to }{\mathop{\mathbf{b}}}\,=0\] \[\Rightarrow \]               \[(3\widehat{\mathbf{i}}+\lambda \widehat{\mathbf{j}}+\widehat{\mathbf{k}})\cdot (2\widehat{\mathbf{i}}-\widehat{\mathbf{j}}+8\widehat{\mathbf{k}})=0\] \[\Rightarrow \]                               \[6-\lambda +8=0\] \[\Rightarrow \]                               \[\lambda =14\]


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