A) \[(0,\,\,0)\]
B) \[(1,\,\,1)\]
C) \[(1,\,\,0)\]
D) \[(0,\,\,1)\]
Correct Answer: B
Solution :
Key Idea: If the equation of ellipse be\[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\], then centre of ellipse be\[(0,\,\,0)\]. Given equation of ellipse be \[\frac{{{(x+y-2)}^{2}}}{9}+\frac{{{(x-y)}^{2}}}{16}=1\] For finding a centre, we put \[x+y-2=0\]and\[x-y=0\] \[\Rightarrow \] \[y=1,\,\,x=1\] \[\therefore \]Required centre is\[(1,\,\,1)\].You need to login to perform this action.
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