A) \[6\mu F\]
B) \[3/2\mu F\]
C) \[2/3\mu F\]
D) \[5\mu F\]
Correct Answer: C
Solution :
The resultant capacitance of three capacitors in series is \[\frac{1}{C'}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}\]You need to login to perform this action.
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