A) octahedral
B) tetrahedral
C) trigonal bipyramidal
D) square planar
Correct Answer: C
Solution :
Key Idea: Write the name of orbitals which are participating in bond formation and then calculate percentage.Hybridisation | Orbitals | % of\[\mathbf{s}\]character | |
[a] | Octahedral | \[s{{p}^{3}}{{d}^{2}}\] | \[16.7%\] |
[b] | Tetrahedral | \[s{{p}^{3}}\] | \[25%\] |
[c] | Trigonal bipyramidal | \[s{{p}^{3}}d\] | \[20%\] |
[d] | Square planar | \[s{{p}^{3}}{{d}^{2}}\] | \[16.7%\] |
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