A) \[+14\]to\[+4\]
B) \[+6\]to\[+2\]
C) \[-7\]to\[-2\]
D) \[+7\]to\[+2\]
Correct Answer: D
Solution :
Key Idea: The sum of oxidation number of all elements in an ion is equal to charge onion. In the reaction \[MnO_{4}^{-}\] changes into \[M{{n}^{2+}}\] Let oxidation state of\[Mn\]in\[MnO_{4}^{-}=x\] \[\therefore \] \[x+(4\times -2)=-1\] \[\therefore \] \[x=+7\] Oxidation state of \[Mn\] in\[M{{n}^{2+}}=+2\] \[\therefore \]the oxidation number of \[Mn\] changes from \[+7\] to \[+2\] during reaction.You need to login to perform this action.
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