A) \[5\]
B) \[5\times {{10}^{-2}}\]
C) \[2\times {{10}^{-4}}\]
D) none of these
Correct Answer: A
Solution :
Key Idea: Equilibrium constant\[{{K}_{c}}=\frac{{{k}_{f}}}{{{k}_{b}}}\] Given \[{{k}_{f}}=2.38\times {{10}^{-4}}\] \[\therefore \] \[{{K}_{c}}=\frac{2.38\times {{10}^{-4}}}{4.76\times {{10}^{-5}}}=5\]You need to login to perform this action.
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