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JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    The latent heat of vaporisation of water is\[2250\,\,J/kg\]. If the work done in the process of vaporisation of \[1\,\,kg\] is \[168\,\,J\], then increase in internal energy will be:

    A) \[1904\,\,J\]                      

    B) \[1984\,\,J\]

    C) \[3202\,\,J\]                      

    D) \[2082\,\,J\]

    Correct Answer: D

    Solution :

    Heat supplied to vaporise the water                 \[dQ=mL\] where \[L\] is the latent heat of vaporisation of water. \[\therefore \]  \[dQ=1\times 2250=2250\,\,J\] According to first law of thermodynamics,                 \[dQ=dU+dW\] or            \[2250=dU+168\] or            \[dU=2250-168\]                 \[=2082\,\,J\]


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