A) \[-53/10\]
B) \[-7/10\]
C) \[7/10\]
D) \[23/10\]
Correct Answer: D
Solution :
Key Idea: In second quadrant \[tan,\,\,cot,\,\,cos\] are negative and sin are positive. Given that, \[3\tan A+4=0\Rightarrow \tan A=-\frac{4}{3}\] Since, \[A\] lies in IInd quadrant \[\therefore \] \[\cot A=-\frac{3}{4},\,\,\cos A=-\frac{3}{5},\,\,\sin A=\frac{4}{5}\]You need to login to perform this action.
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