A) \[25\]
B) \[14\]
C) \[11\]
D) \[73\]
Correct Answer: A
Solution :
Amplification factor is defined as the ratio of change in plate potential \[(\Delta {{V}_{p}})\] to produce certain change in plate current \[(\Delta {{i}_{p}})\] to the change in grid potential \[(\Delta {{V}_{g}})\] for the same change in plate current\[i.e,.\] \[\mu =-{{\left( \frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}} \right)}_{\Delta {{i}_{p}}=\text{constant}}}\] Here, \[\Delta {{V}_{p}}=220-200=20\,\,V\] \[\Delta {{V}_{g}}=-1.3-(-0.5)\] \[=-0.8\,\,V\] \[\mu =-\left( \frac{20}{-0.8} \right)=25\] Note: Amplification factor is unitless and dimensionless.You need to login to perform this action.
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