A) \[\frac{12}{13}\]
B) \[\frac{11}{10}\]
C) \[2\]
D) \[\frac{10}{11}\]
Correct Answer: A
Solution :
The three resistances shown in figure are connected in parallel. So, their equivalent resistance is given by \[\frac{1}{R}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\] \[=\frac{6+4+3}{12}=\frac{13}{12}\] \[R=\frac{12}{13}\Omega \] Note: The equivalent resistance in parallel combination is less than either of the resistances.You need to login to perform this action.
You will be redirected in
3 sec