A) \[3\]
B) \[6\]
C) \[4\]
D) \[1.5\]
Correct Answer: B
Solution :
\[{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2{{H}^{+}}+SO_{4}^{2-}\] \[\because \]\[1\]mole\[{{H}_{2}}S{{O}_{4}}=2g-\]equivalent of\[{{H}_{2}}S{{O}_{4}}\] \[\therefore \]\[3\]mole\[{{H}_{2}}S{{O}_{4}}=2\times 3g-\]equivalent of\[{{H}_{2}}S{{O}_{4}}\] \[=6\,\,g-\]equivalent of\[{{H}_{2}}S{{O}_{4}}\]You need to login to perform this action.
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