A) \[0.46\]
B) \[0.61\]
C) \[0.95\]
D) \[0.73\]
Correct Answer: B
Solution :
Key Idea:\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)PC{{l}_{5}}(g)\] \[\therefore \] \[\Delta {{n}_{g}}=1-2=-1\] Given \[{{K}_{c}}=26\] \[T={{250}^{o}}C=250+273=523\,\,K\] \[R=0.0821\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[=26{{(0.0821\times 523)}^{-1}}\] \[=26\times \frac{1}{0.0821\times 523}\] \[=0.61\]You need to login to perform this action.
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