A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}OH\]
B) \[\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\]
D) None of the above
Correct Answer: C
Solution :
Key Idea: \[{{1}^{o}}\] carbon atom has only alkyl group attached to it. \[{{2}^{o}}\]carbon atom has 2 alkyl group attached to it. \[{{3}^{o}}\]carbon atom has 3 alkyl group attached to it. [a]\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ |{{3}^{o}} \end{smallmatrix}}{\mathop{C}}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{{{2}^{o}}}{\mathop{C}}}\,H-\overset{{{1}^{o}}}{\mathop{C}}\,{{H}_{2}}OH\] \[\therefore \]It has\[1,\,\,2,\,\,{{3}^{o}}\]hydroxyl groups. [b]\[\underset{\begin{smallmatrix} | \\ OH \\ {{1}^{o}} \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \\ {{2}^{o}} \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix} | \\ OH \\ {{1}^{o}} \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}\] \[\therefore \]It has \[{{1}^{o}}\] and \[{{2}^{o}}\] hydroxyl groups. [c]\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{{{2}^{o}}}{\mathop{C}}}\,H-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{{{2}^{o}}}{\mathop{C}}}\,H-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{{{2}^{o}}}{\mathop{C}}}\,H-C{{H}_{3}}\] \[\therefore \]It has all \[{{2}^{o}}\] hydroxyl groups.You need to login to perform this action.
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