A) \[3.4\,\,g\]
B) \[0.034\,\,g\]
C) \[0.34\,\,g\]
D) \[0.17\,\,g\]
Correct Answer: C
Solution :
Key Idea: First write balanced chemical reaction and then find the answer. \[BaC{{l}_{2}}+{{H}_{2}}S\xrightarrow{{}}BaS+2HCl\] Molecular mass of\[{{H}_{2}}S=1\times 2\times 32=34\] Molecular mass of\[BaS=137+32=169\] Given mass of\[BaS=1.69\,\,g\] According to reaction. \[\because \]\[169\,\,g\] of \[BaS\] is obtained by\[=34\,\,g\]of\[{{H}_{2}}S\] \[\therefore \]\[1.69\,\,g\] of \[BaS\] is obtained by\[=\frac{34}{169}\times 1.69\] \[=0.34\,\,g\]of\[{{H}_{2}}S\]
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