A fireman wants to slide down a rope. The breaking load for the rope is \[\frac{3}{4}th\] of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is\[g)\]
A)\[\frac{g}{2}\]
B)\[\frac{g}{4}\]
C)\[\frac{3g}{4}\]
D)\[zero\]
Correct Answer:
B
Solution :
Let the resultant acceleration of fireman be a then \[R=mg-ma\] Given, \[R=\frac{3}{4}mg\] \[\therefore \] \[\frac{3}{4}mg=mg-ma\] \[\Rightarrow \] \[a=\frac{g}{4}\]