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JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    The velocity of a body moving with uniform acceleration at a given instant of time \[t\] is\[10\,\,m/s\]. After \[5\,\,s\] its velocity is \[20\,\,m/s\]. Distance travelled in that time is:

    A) \[300\,\,m\]                      

    B) \[400\,\,m\]

    C) \[150\,\,m\]                      

    D)  \[75\,\,m\]

    Correct Answer: D

    Solution :

    From equation of motion                 \[v=u+at\] Given,   \[v=20\,\,m/s,\,\,u=10\,\,m/s,\,\,t=5\,\,s\] \[\therefore \]  \[a=\frac{10}{5}=2m/{{s}^{2}}\] Also,      \[{{v}^{2}}={{u}^{2}}+2a\,\,s\]                 \[{{(20)}^{2}}={{(10)}^{2}}+2\times 2\,\,s\] \[\Rightarrow \]               \[s=\frac{300}{4}=75\,\,m\]


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