A) \[N{{a}_{2}}S{{O}_{4}}\cdot A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24{{H}_{2}}O\]
B) \[CuS{{O}_{4}}\cdot A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24{{H}_{2}}O\]
C) \[FeS{{O}_{4}}\cdot {{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot 6{{H}_{2}}O\]
D) \[{{K}_{2}}S{{O}_{4}}\cdot F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 2{{H}_{2}}O\]
Correct Answer: C
Solution :
(i)\[N{{a}_{2}}S{{O}_{4}}\cdot A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24{{H}_{2}}O\]and \[{{K}_{2}}S{{O}_{4}}\cdot F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24{{H}_{2}}O\]are alum. (ii)\[FeS{{O}_{4}}\cdot {{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot 6{{H}_{2}}O\]is Mohr?s salt.You need to login to perform this action.
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