A) \[\frac{g}{2}\]
B) \[\frac{g}{4}\]
C) \[\frac{3g}{4}\]
D) \[zero\]
Correct Answer: B
Solution :
Let the resultant acceleration of fireman be a then \[R=mg-ma\] Given, \[R=\frac{3}{4}mg\] \[\therefore \] \[\frac{3}{4}mg=mg-ma\] \[\Rightarrow \] \[a=\frac{g}{4}\]You need to login to perform this action.
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