A) \[16\,\,days\]
B) \[2\,\,days\]
C) \[4\,\,days\]
D) \[8\,\,days\]
Correct Answer: D
Solution :
Key Idea: Time period of parking orbit is 1 day. From Kepler's third law \[{{T}^{2}}=k{{R}^{3}}\] where, \[T\] is time period and \[R\] is radius of earth. Given,\[{{T}_{1}}=1\,\,day,\,\,{{R}_{2}}=4{{R}_{1}}\] \[\therefore \] \[\frac{{{T}_{2}}}{1}={{\left( \frac{4{{R}_{1}}}{{{R}_{1}}} \right)}^{3/2}}\] \[\Rightarrow \] \[{{T}_{2}}={{(4)}^{3/2}}=8\,\,days\]You need to login to perform this action.
You will be redirected in
3 sec