A) \[400\,\,Hz\]
B) \[300\,\,Hz\]
C) \[200\,\,Hz\]
D) \[100\,\,Hz\]
Correct Answer: C
Solution :
As stretched string of 1m long is plucked at a distance of \[25\,\,cm\] from end, so there will be \[2\] loops. Frequency, \[n=\frac{p}{2l}\sqrt{\frac{T}{m}}\] Given, \[p=2,\,\,l=1\,\,m,\,\,T=20N,\] \[m=0.5\times {{10}^{-3}}kg/m\] \[\therefore \] \[n=\frac{2}{2\times 1}\sqrt{\frac{20}{0.5\times {{10}^{-3}}}}\] \[\Rightarrow \] \[n=200\,\,Hz\]You need to login to perform this action.
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