A) \[300\]
B) \[600\]
C) \[925\]
D) \[1200\]
Correct Answer: C
Solution :
Given, Glucose solution\[=0.5\,\,g/L\]is isotonic with \[2.5\,\,g/L\] solution of organic compound. Molarity of glucose \[=\frac{mass\,\,of\,\,glucose/molecular\,\,mass\,\,of\,\,glucose}{V\,\,of\,\,solution\,\,in\,\,L}\]\[=\frac{0.5/180}{1}=0.0027\,\,M\] \[\because \]Glucose solution -is: isotonic with, organic compound solution. \[\therefore \]molarity of glucose \[=\]molarity of organic compound \[=0.0027\,\,M\] Molarity of organic compound \[=\frac{molecular\,\,mass\,\,of\,\,organic\,\,compound}{V\,\,of\,\,solution}\] or\[0.0027=\frac{2.5/molecular\,\,mass}{1}\] \[\therefore \] molecular mass\[=\frac{2.5}{0.0027}\] \[=925\]
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