A) \[x+3y=21\]
B) \[2x-3y=7\]
C) \[x+7y=31\]
D) \[2x+3y=21\]
Correct Answer: C
Solution :
Key Idea: In a square two diagonals intersect perpendicularly. Since, equation of one diagonal of a square is \[7x-y+8=0\] \[\therefore \]The equation of another diagonal will be\[x+7y+\lambda =0\]. This diagonal passes through the point\[(-4,\,\,5)\]. \[\therefore \] \[-4+35+\lambda =0\Rightarrow \lambda =-31\] \[\therefore \]The required diagonal is, \[x+7y=31\]You need to login to perform this action.
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