A) \[F=i\,\,l\,\,B\,\,\sin \,\,\theta \]
B) \[F={{i}^{2}}l\,\,{{B}^{2}}\sin \theta \]
C) \[F=i\,\,l\,\,B\,\,\cos \theta \]
D) \[F=\frac{{{i}^{2}}l}{B}\sin \theta \]
Correct Answer: A
Solution :
The general equation for the force acting on a current carrying conductor placed in a magnetic field \[(B)\] is given by \[F=ilB\,\,\sin \,\,\theta \] Note: The expression can also be obtained from Lorentz force equation.You need to login to perform this action.
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