A) exactly at the target
B) \[10\,\,cm\] below the target
C) \[10\,\,cm\] above the target
D) \[5\,\,cm\] above the target
Correct Answer: D
Solution :
We know that distance \[(s)=\]speed\[(v)\times \]time \[(t)\] Given,\[v=500\,\,m{{s}^{-1}},\,\,s=50\,\,m\] \[\therefore \] \[t=\frac{50}{500}=0.1\,\,s\] From equation of motion, for vertical displacement \[h=ut+\frac{1}{2}g{{t}^{2}}\] Given, \[u=0,\,\,t=0.1\,\,s\] \[\therefore \] \[h=\frac{1}{2}\times 10\times {{(0.1)}^{2}}=0.05\,\,m=5\,\,cm\].You need to login to perform this action.
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