A) \[{{I}_{2}}+10HN{{O}_{3}}\xrightarrow[{}]{{}}2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O\]
B) \[3Cu+8HN{{O}_{3}}\xrightarrow{{}}3Cu{{(N{{O}_{3}})}_{2}}\]\[+2NO+4{{H}_{2}}O\]
C) \[4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\]\[+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
D) \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{3}}\xrightarrow{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\]
Correct Answer: D
Solution :
[a]\[{{I}_{2}}+10\overset{+5}{\mathop{HN{{O}_{3}}}}\,\xrightarrow[{}]{{}}\] \[2HI{{O}_{3}}+\overset{+2}{\mathop{10NO}}\,+4{{H}_{2}}O\] In the reaction \[HN{{O}_{3}}\] is acting as oxidising agent because its oxidation state is decreasing from\[+5\] to\[+2\]. [b]\[3Cu+\overset{+5}{\mathop{8HN{{O}_{3}}}}\,\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\] \[3Cu{{(N{{O}_{3}})}_{2}}+\overset{+2}{\mathop{2NO}}\,+4{{H}_{2}}O\] It is reaction in which \[HN{{O}_{3}}\] is acting as oxidising agent because oxidation number of nitrogen is decreasing^. [c]\[4Zn+\overset{+5}{\mathop{10HN{{O}_{3}}}}\,\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\] \[+\overset{+2}{\mathop{N{{H}_{4}}N{{O}_{3}}}}\,+3{{H}_{2}}O\] \[\therefore \]It is also a reaction, in which \[HN{{O}_{3}}\] is oxidizing agent. [d] \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{5}}\xrightarrow[{}]{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\] \[{{P}_{2}}{{O}_{5}}\]is dehydrating agent. So in this reaction \[HN{{O}_{3}}\] does not act as oxidizing agent.
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