A) \[135.0\]
B) \[172.0\]
C) \[90.0\]
D) \[180.0\]
Correct Answer: D
Solution :
Key Idea: Molecular mass\[=\frac{1000\times {{k}_{f}}\times w}{\Delta {{T}_{f}}\times W}\] Given\[{{k}_{f}}=1.86\] \[w=\]mass of solute\[=4.5\,\,g\] \[W=\]mass of solvent\[=100\,\,g\] \[\Delta {{T}_{f}}=\]Depression in freezing point\[={{0.465}^{o}}C\] \[\therefore \]Molecular weight of solute \[=\frac{1000\times 1.86\times 4.5}{0.465\times 100}\] \[=180\]You need to login to perform this action.
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