A) \[{{45}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{30}^{o}}\]
D) \[{{15}^{o}}\]
Correct Answer: C
Solution :
To avoid dependence on friction, the rods are banked at the turn so that the outer part of the road is somewhat lifted compared to the inner part. Applying Newton's second law along the radius and the first law in the vertical direction. \[N\sin \theta =\frac{m{{v}^{2}}}{r}\] and \[N\cos \theta =mg\] From these two equations, we get \[\tan \theta =\frac{{{v}^{2}}}{rg}\] Given,\[v=32\,\,m{{s}^{-1}},\,\,r=180\,\,m,\,\,g=9.8\,\,m/{{s}^{2}}\] Hence, \[\tan \theta =\frac{{{(32)}^{2}}}{180\times 9.8}\] or \[\theta ={{30}^{o}}\]You need to login to perform this action.
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