A) \[20\]
B) \[8\]
C) \[10\]
D) \[18\]
Correct Answer: A
Solution :
Key Idea: The period of \[|\sin x|\] is\[n\]. \[\int_{0}^{10\pi }{|\sin x|}\,\,dx\] \[=\left[ \int_{0}^{\pi /2}{\sin x\,\,dx+\int_{\pi /2}^{\pi }{\sin x}\,\,dx} \right]\] \[=10[-\cos x]_{0}^{\pi /2}+[-\cos x]_{\pi /2}^{\pi }\] Alternative Solution: \[\therefore \]Required area \[=10\int_{0}^{\pi }{\sin x}\,\,dx\] \[=10[-\cos x]_{0}^{\pi }=-10(\cos \pi -\cos 0)=20\]You need to login to perform this action.
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