A) \[\frac{9}{2}sq\,\,unit\]
B) \[\frac{43}{6}sq\,\,unit\]
C) \[\frac{35}{6}sq\,\,unit\]
D) none of these
Correct Answer: A
Solution :
Required area\[=\int_{0}^{3}{({{y}_{1}}-{{y}_{2}})}\,dx\] \[=\int_{0}^{3}{(2x-{{x}^{2}})}-(-x)dx\] \[=\int_{0}^{3}{(3x-{{x}^{2}})}\,\,dx\] \[=\left[ \frac{3{{x}^{2}}}{2}-\frac{{{x}^{3}}}{3} \right]_{0}^{3}\] \[=\frac{27}{2}-9\] \[=\frac{9}{2}sq\,\,unit\]You need to login to perform this action.
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