A) \[5\sqrt{2}m/s\]
B) \[2\sqrt{5}m/s\]
C) \[3\sqrt{5}m/s\]
D) \[5\sqrt{3}m/s\]
Correct Answer: D
Solution :
Key Idea: Maximum velocity at lowest point is \[\sqrt{5}\]times maximum velocity at highest point. Diameter \[AB\] of circle is\[3\,\,m\] Therefore, radius\[r=\frac{3}{2}m\] velocity at\[A(v)=\sqrt{5gr}\] Given,\[g=10\,\,m/{{s}^{2}},\,\,r=\frac{3}{2}m\] \[\therefore \] \[v=\sqrt{5\times 10\times \frac{3}{2}}=5\sqrt{3}m/s\]You need to login to perform this action.
You will be redirected in
3 sec