A) \[64\,\,g\]
B) \[16\,\,g\]
C) \[32\,\,g\]
D) \[8\,\,g\]
Correct Answer: A
Solution :
If\[{{r}_{x}}=r\]then\[{{r}_{C{{H}_{4}}}}=2r\] \[{{M}_{C{{H}_{4}}}}=12+4=16\] \[{{M}_{X}}=?\] We know that, \[\frac{{{r}_{C{{H}_{4}}}}}{{{r}_{x}}}=\sqrt{\frac{{{M}_{X}}}{{{M}_{C{{H}_{4}}}}}}\] \[\frac{2r}{r}=\sqrt{\frac{{{M}_{x}}}{16}}\] \[{{(2)}^{2}}=\frac{{{M}_{x}}}{16}\] \[4=\frac{{{M}_{x}}}{16}\] or \[{{M}_{x}}=64\]
You need to login to perform this action.
You will be redirected in
3 sec
