A) increasing from \[-1\] to \[1\]
B) decreasing from \[-1\] to \[0\]
C) decreasing from \[0\] to \[1\]
D) none of the above
Correct Answer: A
Solution :
Since, \[2\pi k-\frac{\pi }{2}\le \sin x\le 2\pi k+\frac{\pi }{2}\] For \[k=0\] \[-\pi /2<\sin x<\pi /2\] which increases from\[-1\]to\[1\]. Similarly, for other values of \[k\] it is increases from\[-1\] to \[1\].You need to login to perform this action.
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