A) \[\frac{5}{8}\]
B) \[\frac{37}{64}\]
C) \[\frac{3}{4}\]
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
Given\[P(A)=P(B)=P(C)=\frac{1}{4}\] \[P(AB)=P(CB)=0\] and \[P(A\cap C)=\frac{1}{8}\] Now, \[P(A+B)=P(A\cup B)\] \[=P(A)+P(B)-P(A\cap B)=\frac{1}{4}+\frac{1}{4}-0=\frac{1}{2}\]You need to login to perform this action.
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