A) \[\frac{1}{2}{{I}_{0}}\]
B) \[\frac{1}{4}{{I}_{0}}\]
C) \[zero\]
D) \[{{I}_{0}}\]
Correct Answer: A
Solution :
\[I={{I}_{0}}{{\cos }^{2}}\theta \] Intensity of polarized light \[=\frac{{{I}_{0}}}{2}\] \[\therefore \]Intensity of un transmitted light \[={{I}_{0}}-\frac{{{I}_{0}}}{2}=\frac{{{I}_{0}}}{2}\]You need to login to perform this action.
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