A) \[22\,\,dyne\]
B) \[20\,\,N\]
C) \[20\,\,dyne\]
D) \[100\,\,N\]
Correct Answer: B
Solution :
The accelerating force on the rocket = upward thrust\[=\frac{\Delta m}{\Delta t}\cdot u\] Given,\[\frac{\Delta m}{\Delta t}=50\times {{10}^{-3}}kg/s,\,\,v=400\,\,m/s\] So, accelerating force\[=50\times {{10}^{-3}}\times 400\] \[=20\,\,N\]You need to login to perform this action.
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