JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    A transformer is used to light \[\text{a}\] \[100\,\,W\] and \[110\,\,V\] lamp from a \[220\,\,V\] mains. If the main current is \[0.5\,\,A\], the efficiency of the transformer is approximately

    A) \[30%\]                               

    B) \[50%\]

    C)  \[90%\]                                              

    D)  \[10%\]

    Correct Answer: C

    Solution :

    The efficiency of transformer \[\text{=}\frac{\text{Energy}\,\,\text{obtained}\,\,\text{from}\,\,\text{the}\,\,\text{secondary}\,\,\text{coil}}{\text{Energy}\,\,\text{given}\,\,\text{to}\,\,\text{the}\,\,\text{primary}\,\,\text{coil}}\] or            \[\eta =\frac{\text{Output}\,\,\text{power}}{\text{Input}\,\,\text{power}}\] or            \[\eta =\frac{{{V}_{s}}{{I}_{s}}}{{{V}_{p}}{{I}_{p}}}\] Given,   \[{{V}_{s}}{{I}_{s}}=100W,\,\,{{V}_{p}}=220\,\,V,\,\,{{I}_{p}}=0.5\,\,A\] Hence,  \[\eta =\frac{100}{225\times 0.5}=0.90=90%\] Note The efficiency of an ideal transformer is \[1\] (or\[100%)\]. But in practice due to loss in energy, the efficiency of transformer is always less than \[1\] (or less than\[100%)\].


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